3x^2-11=6x+13

Solution for 3x^2-11=6x+13 equation:

3x^2-11=6x+13

We move all terms to the left:

3x^2-11-(6x+13)=0

We get rid of parentheses

3x^2-6x-13-11=0

We add all the numbers together, and all the variables

3x^2-6x-24=0

a = 3; b = -6; c = -24;
Δ = b2-4ac
Δ = -62-4·3·(-24)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*3}=\frac{24}{6}
=4
$